HELP WITH BATCH RENAMING PLEASE :)

[smadgos]

Hello guys,
Hopefully i am posting this one in the right place.
I need to batch rename photos from my camera in a specific way and can't find how to.
What i basically need is to batch rename my photos so that each 3 photos will carry the same number but with a different letter (A\B\C)
The photos will be sort by date taken before the renaming.

For Example:
These are the photo's names in the folder:
IMG_6001
IMG_6002
IMG_6003
IMG_6004
IMG_6005
IMG_6006
IMG_6007
IMG_6008
IMG_6009

The result i need is:
1A
1B
1C
2A
2B
2C
3A
3B
3C

ANY INFO would be HIGHLY appriciated!
Thanks in advance!
Elad

 

[flyinmac]

The tool I like is called:

A Better Finder Rename

You can find it in the Mac App Store.

You can also google for it if you prefer that route. I've used it before, and it's a very powerful tool for these purposes.

You can read about it and other similar tools in an article published in MacWorld at the following link.

http://www.macworld.com/article/208...me-review-easily-rename-batches-of-files.html

I think you'll find that it's what you're looking for.

Always test on copies until you verify that it is doing what you expect.

 

[Padaung]

Another option is Name Changer

However, I'm not sure it will allow renaming with a sequence of letters. However, renaming with a sequence of numbers is a standard with any renaming software as far as I know.

 

[Toutou]

Copy and paste this into Terminal. I tested it on a folder of (IMG_6001.jpg IMG_6002.jpg IMG_6003.jpg ….)

bash -c 'clear;echo "Please drag n drop the target folder into this window."; echo "Should look like this: /path/to/folder"; echo -n "Input: "; read folder; cd $folder; if [ $? -ne 0 ] ; then echo "Wrong input, cant access directory, aborting"; read; exit; fi; I=0; for filename in $(ls); do let "A=((I%9)/3)+1"; let "B=I%3"; case "$B" in 0) B=A;; 1) B=B;; 2) B=C;; esac; extension="$(echo $filename | grep -o "\.[^\.]*$")"; newname="$A$B$extension"; echo "Renaming $filename to $newname"; mv $filename $newname; let "I++"; done; echo "---All done!---"; read;'

 

[smadgos]

Toutou - you are AMAZING!!! Thank you so much for this.
It worked almost Perfectly and maybe you could figure out how to make it perfect.
I had 1500 images in the folder therefore i expected the last files would be renamed " 500 a/b/c "
the problem is that the code is somehow limited to only renaming the files up to 3 a/b/c
all photos that should have been renamed from 4a and on simply disappeared from the folder.
Luckily i ran this test on a COPY folder so i still have the original images.
Can you help me with this PLEASE?
[doublepost=1491076201][/doublepost]

Copy and paste this into Terminal. I tested it on a folder of (IMG_6001.jpg IMG_6002.jpg IMG_6003.jpg ….)

bash -c 'clear;echo "Please drag n drop the target folder into this window."; echo "Should look like this: /path/to/folder"; echo -n "Input: "; read folder; cd $folder; if [ $? -ne 0 ] ; then echo "Wrong input, cant access directory, aborting"; read; exit; fi; I=0; for filename in $(ls); do let "A=((I%9)/3)+1"; let "B=I%3"; case "$B" in 0) B=A;; 1) B=B;; 2) B=C;; esac; extension="$(echo $filename | grep -o "\.[^\.]*$")"; newname="$A$B$extension"; echo "Renaming $filename to $newname"; mv $filename $newname; let "I++"; done; echo "---All done!---"; read;'

#5
Toutou - you are AMAZING!!! Thank you so much for this.
It worked almost Perfectly and maybe you could figure out how to make it perfect.
I had 1500 images in the folder therefore i expected the last files would be renamed " 500 a/b/c "
the problem is that the code is somehow limited to only renaming the files up to 3 a/b/c
all photos that should have been renamed from 4a and on simply disappeared from the folder.
Luckily i ran this test on a COPY folder so i still have the original images.
Can you help me with this PLEASE?

 

[jasnw]

I'm not a bash expert, but I think if you change the section in the code string that reads

do let "A=((I%9)/3)+1"

to

do let "A=(I/3)+1"

that should do what you want. As always, try this out on a copy before risking everything.

 

[Toutou]

I'm not a bash expert, but I think if you change the section in the code string that reads

do let "A=((I%9)/3)+1"

to

do let "A=(I/3)+1"

that should do what you want. As always, try this out on a copy before risking everything.

Exactly! I left there a modulo operation from an earlier attempt.

correct:

bash -c 'clear;echo "Please drag n drop the target folder into this window."; echo "Should look like this: /path/to/folder"; echo -n "Input: "; read folder; cd $folder; if [ $? -ne 0 ] ; then echo "Wrong input, cant access directory, aborting"; read; exit; fi; I=0; for filename in $(ls); do let "A=(I/3)+1"; let "B=I%3"; case "$B" in 0) B=A;; 1) B=B;; 2) B=C;; esac; extension="$(echo $filename | grep -o "\.[^\.]*$")"; newname="$A$B$extension"; echo "Renaming $filename to $newname"; mv $filename $newname; let "I++"; done; echo "---All done!---"; read;'