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waloshin

macrumors 68040
Original poster
Oct 9, 2008
3,562
394
Sometimes I am stupid , but anyways:

27 + (2a -5)^2

The answer is (2a) (9 -6a + 15 + 4a -20a +25)

Where does the -20a come from

(x+6)^3 -y^3

The answer is (x + 6)(x^2 + 12x + 36 + xy + 6y + y^2)

Where does the 12x come from

Thanks
 
That answer can't be correct since every term has an 'a' in it. For example, if a=0 then we have
27 + (2a -5)^2
= 27 + (0-5)^2
= 27 + (-5)^2
= 27 + 25
= 52​
but
(2a) (9 - 6a + 15 + 4a -20a +25)
(2x0) (9 - 6x0 + 15 + 4x0 -20x0 +25)
0 (9 - 0 + 15 + 0 - 0 +25)
0​
They aren't equal, so that answer is wrong. Who told you it was right?

Let's do the problem correctly instead. When you multiple 2a-5 by 2a-5, you multiply all four combinations of terms. It's the FOIL rule: First, Outside, Inside, Last.:
27 + (2a -5)^2
27 + (2a -5) x (2a -5)
27 + (2a x 2a) + (2a x -5) + (-5 x 2a) + (-5 x -5)​
Simplifying each term:
27 + (2a x 2a) + (2a x -5) + (-5 x 2a) + (-5 x -5)
27 + 4a^2 - 10a - 10a + 25​
Combining like terms:
27 + 4a^2 - 10a - 10a + 25
4a^2 + (-10a -10a) + (27 + 25)
4a^2 - 20a + 52​
 
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