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touchher

macrumors regular
Original poster
Nov 23, 2007
128
0
I don't understand how to do these problems/ set it up. Any help would be greatly appreciated. Answer is 18g.

a jeweler has five rings, each weighing 18 g, made of an alloy of 10% silver and 90% gold. he decided to melt down the rings and add enough silver to reduce the gold content to 75%. how much silve should he add?
 
Okay, 5 rings each 18g, so total weight is 5*18 = 90g

Now, they are 10% silver and 90% gold, so 9g of silver and 81g of gold.

Want to add silver, until gold content is 75%. Thus, let's suppose the amount needed to be added is x.

So then there will be (9+x)g of silver, 81g of gold for a total weight of (90+x)g

Gold needs to be 75% of the total, so we know that 81/(90+x) = 0.75

Re-arranging the final equation, gives us 81 = 0.75*(90+x)
Therefore 81 = 67.5 + 0.75x, or 0.75x = 13.5, or x = 18g

So 18g of silver needs to be added
 
Okay, 5 rings each 18g, so total weight is 5*18 = 90g

Now, they are 10% silver and 90% gold, so 9g of silver and 81g of gold.

Want to add silver, until gold content is 75%. Thus, let's suppose the amount needed to be added is x.

So then there will be (9+x)g of silver, 81g of gold for a total weight of (90+x)g

Gold needs to be 75% of the total, so we know that 81/(90+x) = 0.75

Re-arranging the final equation, gives us 81 = 0.75*(90+x)
Therefore 81 = 67.5 + 0.75x, or 0.75x = 13.5, or x = 18g

So 18g of silver needs to be added

Are you superman??? How in gods name did you work that out????
 
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