macOS math operation

[gonche1124]

Hello,

I have two strings and I want to divide the length of each word and round up the result.
Can anyone help with this?

I've tried it with NSDecimalNumber but I get a bucnh of errors.

Thank you

Andres

 

[kainjow]

[str length] returns an int representing the number of characters. You can then divide it like any other number in C. The random() function can be used to round up a double.

If you still need help, post what code you're working with.

 

[lee1210]

The random() function can be used to round up a double.

I'm guessing you meant round(double), not random()... You'd probably get a very different result than you're hoping calling random.

-Lee

 

[chown33]

I've been rounding with random() for years. It keeps the testers on their toes. No comment about all those avionics and nuclear-plant control systems I helped write.

 

[kainjow]

I'm guessing you meant round(double), not random()... You'd probably get a very different result than you're hoping calling random.

-Lee

hehe oops, that is what I meant. Not sure why I put random

 

[lloyddean]

It's unclear what you're asking for but the closest seems to be rounding of real numbers to integers, so ...

	#include <math.h>

	double	n;
	float	f;
	double	d;

	n = 3.4;
	f = floorf(n);	// results = 3
	d = floor(n);	// results = 3
	f = ceilf(n);	// results = 4
	d = ceil(n);	// results = 4
	f = roundf(n);	// results = 3
	d = round(n);	// results = 3


	n = 3.6;
	f = floorf(n);	// results = 3
	d = floor(n);	// results = 3
	f = ceilf(n);	// results = 4
	d = ceil(n);	// results = 4
	f = roundf(n);	// results = 4
	d = round(n);	// results = 4

 

[gonche1124]

It's unclear what you're asking for but the closest seems to be rounding of real numbers to integers, so ...

	#include <math.h>

	double	n;
	float	f;
	double	d;

	n = 3.4;
	f = floorf(n);	// results = 3
	d = floor(n);	// results = 3
	f = ceilf(n);	// results = 4
	d = ceil(n);	// results = 4
	f = roundf(n);	// results = 3
	d = round(n);	// results = 3


	n = 3.6;
	f = floorf(n);	// results = 3
	d = floor(n);	// results = 3
	f = ceilf(n);	// results = 4
	d = ceil(n);	// results = 4
	f = roundf(n);	// results = 4
	d = round(n);	// results = 4

Thanks that was really helpfull!!!

 

[jared_kipe]

Just remember that you'll need to typecast the int that is returned by
-(NSUInteger) length;

such as

unsigned int test1, test2;
test1 = [@"test1 string" length]; // 12
test2 = [@"test2 string 1234" length]; // 17

double result;
result = (double)test1/test2; // ~0.7

NSLog(@"result = %0.2d", result); // prints "result = 0.71"
result = round(result);
NSLog(@"result = %0.2d", result); // prints "result = 1.00"




Just remember one thing, the round function rounds UP .6 and rounds DOWN .5 Unlike how you learned in elementary school.