Again, you posted a mass of code that is full of syntax errors and missing what is needed to run the code to see why it doesn't work.
I also noticed that you almost always screw up your code tags. You enter them as /[code_tag] instead of [/code_tag]
This tells me two things:
1 - You don't pay attention to the message you entered which makes me thing you don't pay attention to the code you enter
2 - You don't bother to look at your posted message to see if it's clear to others, you would instantly notice the formatting is off
You can still test your code. You'd be amazed at how many web sites run on Ruby, Python, etc which are 'interpreted' languages (not 'run-time compiled'). Most forums runs PHP which is interpreted!
[doublepost=1479301353][/doublepost]
Code:
#include <stdio.h>
#include <string.h>
void main (void)
{
char num[10] = "iiiiiiiii\n";
char cmd[75];
int files;
FILE *fp;
char *scan_data_home = "~";
char *end;
strcpy (cmd, "ls ");
strcat (cmd, scan_data_home);
strcat (cmd, " | wc -l");
fp = popen (cmd, "r");
while (fgets (num, sizeof (num) - 1, fp) != NULL) {
printf ("\nValue of the char array 'num': %s\n", num);
}
files = (int) strtol (num, &end, 10);
printf ("Value of 'int files': %d\n", files);
printf ("Each value of the num char array:\n");
printf ("num[0] %x\n", num[0]);
printf ("num[1] %x\n", num[1]);
printf ("num[2] %x\n", num[2]);
printf ("num[3] %x\n", num[3]);
printf ("num[4] %x\n", num[4]);
printf ("num[5] %x\n", num[5]);
printf ("num[6] %x\n", num[6]);
printf ("num[7] %x\n", num[7]);
}
Code:
$ ./a.out
While loop output: 10
10
num[0] 31
num[1] 30
num[2] a
num[3] 0
num[4] 69
num[5] 69
num[6] 69
num[7] 69
If you look at an ASCII chart you'll see each value (in hex) of the num array
So you see the string that contains '10' ends up really holding
'1', '0', '\n', NULL, 'i', 'i', 'i', 'i'
The i's are left there so you can see they aren't overwritten (I set char num[] to 'iiiiiiii' at the beginning of the code. But C sees the NULL it doesn't care and quits processing the array as a string.
