macOS Quick question about Python loops...

[ZipOTrousers]

I'm new to learning Python and haven't programmed much since I left school at the beginning of the summer. Im trying to write a program that will give a user 3 attempts to guess my name:

count = 0
name = raw_input("Try and guess my name: ")

if name != "Andrew":
    count + 1
else:
    print "Well done, thats right!"
    
while name != "Andrew" and count < 3:
    print "Sorry, try again!"

As it is, if the user inputs an incorrect name instead of displaying the error message and re asking for the name, it just gets trapped and repeatedly displays the error message until the program is stopped. Now in something I'm familiar with like VB I'd know how to do this, but with python I don't know how to loop the whole asking for input process until count = 3. This is an exercise from the wikibook on Python btw. How do i structure the program to do this? Thanks.

 

[lee1210]

I'm new to learning Python and haven't programmed much since I left school at the beginning of the summer. Im trying to write a program that will give a user 3 attempts to guess my name:

count = 0
name = raw_input("Try and guess my name: ")

if name != "Andrew":
    count + 1
else:
      print "Well done, thats right!"
    
while name != "Andrew" and count < 3:
    print "Sorry, try again!"

As it is, if the user inputs an incorrect name instead of displaying the error message and re asking for the name, it just gets trapped and repeatedly displays the error message until the program is stopped. Now in something I'm familiar with like VB I'd know how to do this, but with python I don't know how to loop the whole asking for input process until count = 3. This is an exercise from the wikibook on Python btw. How do i structure the program to do this? Thanks.

Not a python pro, but I think it should be:

count = 0
name = ""
while name != "Rumpelstiltskin" and count < 3:
  name = raw_input("Try and guess my name: ")

  if name != "Rumpelstiltskin":
    count + 1
    print "Sorry, try again!"
  else:
    print "Well done, thats right!"

-Lee

 

[HiRez]

Don't you need to increment by

count = count + 1

or

count += 1

? "count + 1" by itself makes no sense because there is no assignment happening there.

 

[lee1210]

Don't you need to increment by

count = count + 1

or

count += 1

? "count + 1" by itself makes no sense because there is no assignment happening there.

Balls, in my reorganization i didn't even notice that.

 

[WebMongol]

Or you can use for loop:

for i in range(3):
    name = raw_input("Try and guess my name: ")
    if name == "Andrew":
        print "well done!"
        break
    else:
        print "try again"

 

[lee1210]

Or you can use for loop:

for i in range(3):
    name = raw_input("Try and guess my name: ")
    if name == "Andrew":
        print "well done!"
        break
    else:
        print "try again"

This is more an issue of style, but I like loops to end when the loop condition is false. break is fine, but I guess I would rank:
exit loop via false condition > break >>> goto

At least there is a loop condition in your example. I really don't enjoy:

while(true/1/.true.)

-Lee