d/dx of e^u = e^u*u', right?.. so it'll be e^x(sinX+cosX)*[x(sinX+cosX)]'
I think... it's been well over a year since I last looked at calc.. or would the [x(sinX+cosX)]' go before the e... shoot!
Wow. Thanks. But... sorry, the sin & cos part wasn't part of the exponent... it's just that times e^x. You would've been right, though, if it had been. The forums need to be updated to handle mathematics symbolism.